Vulcan Logic

[Zephrah 0]

#1

There are three blocks on a table, one red, one yellow, and one blue, your challenge is to remove two of them. If you remove the red one then you must also remove the blue one, and if you remove the blue one, you must remove the yellow one.

[Images 0]

remove the blue one. Pretty easy, after that you're forced to take the yellow. You've taken 2.

[Aaron_Westler 0]

It's even easier...take the red one and you must take blue

Take the blue one and you must take the yellow.

 

By giving you those mandates (you need to take that if you took this) it makes you forget that you need to take two anyway. <_<

[Seiben 0]

It's even easier...take the red one and you must take blue

Take the blue one and you must take the yellow.

 

Yeah, but then that's three. It only says you only have to take two. Heh.. gotta watch out for those trick questions. <_<

[Travis Kroells 0]

Hans, I'm ashamed. You even mentioned it was a trick question.

 

Simple remove the yellow. Theres no mandate against removing it on it's own. No where did it say that you had to remove one to remove the yellow.

[koolaidman 0]

Hans, I'm ashamed. You even mentioned it was a trick question.

 

Simple remove the yellow. Theres no mandate against removing it on it's own. No where did it say that you had to remove one to remove the yellow.

well you have to remove towo so be more lgical and skip an entire step and just take the blue

 

step1 take yellow

step2 take blue

 

or

 

step one take blue and the yellow is automatically taken next

 

viola

[Grom 0]

well you have to remove towo so be more lgical and skip an entire step and just take the blue

 

step1 take yellow

step2 take blue

 

or

 

step one take blue and the yellow is automatically taken next

 

viola

OR destoy the red one with your phaser rifle.

[Darrik 0]

OR destoy the red one with your phaser rifle.

but then it's Klingon logic

[Dumbass 0]

Vulcans play with blocks?

[Guest STSF Sketti]

vulcan logic would dictate that the exercise is pointless, as it involves emotions associated with colors. obviously, this test was designed by a human, as there is no infinite set of outcomes.

[Zephrah 0]

Well done. The courest answer is indead to take the blue, and yellow.

 

#2 There are two lenghths of rope. Each one can burn in exactly 1 hour. They are not necessarily of the same length or width as each other. They also are not of uniform width (may be wider in middle then on end), thus burning half the rope is not necessarily 1/2 hour.

 

By burning the ropes, how do you measure exactly 45 minutes worth of time?

[Dumbass 0]

Trade the ropes for a 3-minute egg timer, and turn the timer over 15 times. <_<

[Tovan 0]

Well since one piece of rope burns an hour regardless of its width and whatnot. So you light it on both ends! Hehe. That gives you half an hour since you burnt it from both ends. While you lid rope 1 (burning from both ends) you lid one end of rope 2 and when rope 1 burns out you know that rope 2 has around 1/2 hour left. Set the other end on fire and you cut that half hour by half ... vola ... 45 minutes ...

 

Or you could do it the easy way and get a timer instead.

 

Also as a Vulcan I must point out that burning such items in your home is HIGHLY not recommended, unless you're suffering from chronic mental instability, you should not try it just to see if it works or not.

 

Message brought to you by Trek Safety 101.3.

Edited March 2, 2005 by Tovan

[Images 0]

You just burn three quarters of one of the ropes. If they both burn for exactly an hour, then three quarters of the rope is 45 minutes right? Or is this some weirdass highly complicated puzzle?

[Guest STSF Sketti]

if this is a vulcan test of logic, we must assume the person the problem is being presented to is vulcan. so. the vulcan answer to this one is - who needs ropes? vulcans are highly calculating, and can keep measure of time in their head. therefore, no burning of rope is necessary, since a true vulcan would know precisely when forty-five minutes had passed.

[Zephrah 0]

Please feel free to post Logic puzzles here. I would enjoy decifering a new problem myself.

[Vex Xiang 0]

Light both ends of rope #1. When #1 is done, fold rope #2 in half and burn both ends.

 

Burning #1 on both ends it will extinguish in 1/2 hour. Folded in half, #2 will burn twice as fast...so burning both ends will extinguish in 15 minutes.

[Darrik 0]

Trade the ropes for a 3-minute egg timer, and turn the timer over 15 times. <_<

but then it's Ferengi logic

[Darrik 0]

Here's an old stupid one:

 

You have two American coins that, when added together, equal 35 cents. One of them is not a quarter. What are the two coins?

Edited March 2, 2005 by Darrik

[NDak 0]

That's a Mathematical impossability, since no other denomations exist that only two of them give you 35 cents:

 

Dime + Dime = 20 cents

Dime+ Nickel= 15 cents

Dime+Penny= 11 cents

FiftyCent Piece goes over the limit

Nickel + Nickel = 10 Cents

Nickel+ Penny= 6 Cents

Penny+ Penny = 2 Cents

 

Therefore the only logical possability (given the way the question was stated) would be a Quarter and a Dime.

 

However, if you mean in abstracts then, saying you have two coins could mean you have two types, not the number, which would open up many other combinations. In which case it's not a question of logic but a badly worded question <_<

Edited March 2, 2005 by NDak

[Darrik 0]

That's Mathematical impossability, since no other demnomations exist that only two of them give you 35 cents:

 

Dime + Dime = 20 cents

Dime+ Nickel= 15 cents

Dime+Penny= 11 cents

FiftyCent Piece goes over the limit

Nickel+ Penny= 6 Cents

 

 

Therefore the only logical possability would be a Quarter and a Dime.

actually, it is quite posible

[Darrik 0]

read the edited post <_<

still, copied it quicker, but, I'll deleate this and the other if you deleate yours

 

jeeze, I just realised this is 700.

Edited March 2, 2005 by Darrik

[Zephrah 0]

Well done, Tovan and Vex Xiang have found solved this one.

 

#3. If I were to think of an integer, greater then zero, but less then four, and the only assistence you could have in decifering the integer that I am thinking of, is one yes or no question what would be an apropriat question?

[Ens_yanksfan 0]

My question would be:

 

Does the number have the same amount of letters of "yes" or "no"?

 

Then, if the number is 2 or 3, you would be giving the answer away by answering yes or no <_<

 

But if the number isn't 2 or 3, then I would know that the answer is definitely 1.

Edited March 2, 2005 by Ens_yanksfan

[Zephrah 0]

You must rember that you are only allowed to ask a question in wich the answer is Yes or No.